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LDSC correlation calculate confidence intervals

Hello,

I found that following formula asked by other colleagues but no answer:

zprime = 0.5 * log((1+rg) / (1-rg))

ci = zprime ± 1.96*se

ci = ((exp(2ci) - 1) / (exp(2ci) + 1))

(rg and se taken from the LDSC output)

I wonder if this is the correct way of calculating 95% CI from LDSC output?

Thank you very much!

correlation intervals confidence genetic ldsc
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written by YL • YL

Hi,

Are you able to find an answer for this? I have the exact question!

YL

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written by YL • YL

Based on my personal thought, I think the se from LDSC output probably needs to be transferred using Delta method based on Fisher transformation, and then used the transformed se to do ci = zprime ± 1.96*se

Hopefully we will get confirmation soon

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written by YL • YL

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