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Reduce saturation by deleting the 3rd position in each codon of DNA seqs. R ape package

I am performing a phylogenentic analysis using specific marker genes.

I selected the aa sequences, aligned them, used as template for aligning the respective nucleotide sequences.

I created a saturation plot with the "ape" package in R, and I can see that same seq are saturated.

In order to have a more robust results I would like, now, to delete the third position in each codon.

Is there a way/program to do this?

I guess this could be done with

seq
test3[seq(1, length(test3), by = 3)] # take only the first nucleotide in the codon

but I cannot find a way of taking only the first one and the second one.

I am also open to any suggestion for different way of doing this task

alignment phylogeny dna r

1 answer

In R you can use negative indices to exclude elements.

Here's an example using one of ape's datasets (not this is an alignment (matrix), not a single sequence (vector) as in your example

Ok, really good thanks!

I might not understand the command AlignmentToFilter[, -seq(1, ncol(AlignmentToFilter), by=3) ] .. but it is apparently skipping the first codon position in my hand while command AlignmentToFilter[, -seq(3, ncol(AlignmentToFilter), by=3) ] worked for me and omitted the 3rd codon position.

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