Command To Extract Row And Column Wise Data
I have the data in table format..
A 345 456 678 878
B 456 789 543 789
A 567 984 234 567
B 546 576 987 133
C 586 986 643 746
A 354 575 263 564
How can I get rows from above data which have data 'A' in first column..{lease help me...
Thanks
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1 answer
If you have linux/mac , you can try following :
grep -w ^A FileName > OutputFielName
OR
- awk '{if($1=="A"){print }}' FileName > OutputFileName
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this is not related to bioinformatics, this is just a basic linux operation. You should have a look at 'grep' or ask stackoverflow.com
I don't consider it a given that everyone trying to do bioinformatics would know what grep is. Thus this person could very well be asking a bioinformatics related question. And thus I consider Ashwin's answer informative, and the fact that he included an awk example beneficial for newbies as well as "experts" alike.