It worked perfectly. Greatly appreciate it.
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arraychip •
find unpaired files
In a folder, there are txt files, all with unique names. After an analysis, new files are generated, in the form of "file name_analyzed.txt". One "_analyzed.txt" file for an input file. Some files, for some unknown reason, don't generate "_analyzed.txt".
So, it looks like:
file1.txt file1_analyzed.txt /
file2.txt file2_analyzed.txt /
**file3.txt** /
file4.txt file4_analyzed.txt /
..
fileN.txt fileN_analyzed.txt
.
How can I list all the files like "file3", with no accompanying pair? Typically, there are over 40,000 files in a folder. Any command-lines to solve this problem?? Thanks
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Joe
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arraychip •
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arraychip •
2 answers
One way.
$ ls -1
file1.txt
file1_analyzed.txt
file2.txt
file3.txt
file3_analyzed.txt
file4_analyzed.txt
# following is needed for bash
$ shopt -s extglob
$ comm -3 <(ls -1 *_analyzed.txt | sed 's/_analyzed.txt//' | sort) <(ls -1 !(*analyzed.txt) | sed 's/.txt//'| sort)
file2
file4
In output column 1: file4_analyzed.txt has no corresponding plain file
In output column 2: file2 has no corresponding _analyzed.txt file
If you only have missing _analyzed.txt files then you should only get one column of output.
$ ls
file1.txt file1_analyzed.txt file2.txt file3.txt file3_analyzed.txt file4_analyzed.txt
$ shopt -s extglob
$ ls !(*_analyzed.txt)
file1.txt file2.txt file3.txt
What have I done wrong?
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GenoMax
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arraychip •
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