thank you,
sorry, no way to consider the effect of time points too?
Hi,
In my experiment, before high temperature treatment (48 c), Arabidopsis cotyledons were pre-heated for 2, 8 and 24 hours. In the other hand I have cotyledons keeping in room temperature for 2, 8 and 24 hours, I mean without pre-heating these cotyledons directly face the high temperature. I don't have any replication
Something like below
I got totally confused if I should use this syntax in cuffdiff
cuffdiff \
-o diff_out \
-b genome.fa \
-p 8 \
-u merged_asm/merged.gtf \
pre-heated-2h.bam, pre-heated-8h.bam, pre-heated-24h.bam, unpre-heated-2h.bam, unpre-heated-8h.bam, unpre-heated-24h.bam
or
cuffdiff \
-o diff_out \
-b genome.fa \
-p 8 \
-L pre,unpre \
-u merged_asm/merged.gtf \
pre-heated-2h.bam, pre-heated-8h.bam, pre-heated-24h.bam, unpre-heated-2h.bam, unpre-heated-8h.bam, unpre-heated-24h.bam
Using the first syntax the cummerbund result was nonsense..and the number of differentially expressed genes was 0, how possible
I am going to know the effect of pre-heating on heat stress tolerance
Please help me to be clear a little bit
Thank you
Assuming there's no effect due to duration of treatment (or that it's minimal):
cuffdiff -o diff_out -b genome.fa -p 8 -L pre,unpre -u merged_asm/merged.gtf pre-heated-2h.bam,pre-heated-8h.bam,pre-heated-24h.bam unpre-heated-2h.bam,unpre-heated-8h.bam,unpre-heated-24h.bam
You should at least put some effort and time (maybe 10 min ?) to read the manual and copy paste?
If you look at the manual, it clearly states:
cuffdiff [options]* <transcripts.gtf> \
<sample1_replicate1.sam[,...,sample1_replicateM.sam]> \
<sample2_replicate1.sam[,...,sample2_replicateM.sam]> ... \
[sampleN.sam_replicate1.sam[,...,sample2_replicateM.sam]]
If you apply that exact command to your data:
cuffdiff -o diff_out -b genome.fa -p 8 -L pre,unpre -u merged_asm/merged.gtf \
pre-heated-2h.bam,pre-heated-8h.bam,pre-heated-24h.bam \
unpre-heated-2h.bam,unpre-heated-8h.bam,unpre-heated-24h.bam
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