If your variable hercoc has only two levels then there is no difference. However, if it has 3 or more levels then there is a difference. You haven't provided any example data, and I am assuming that hercoc is numeric.

Using a more concrete example:

library(survival)

attach(lung)

head(lung)

#     inst time status age sex ph.ecog ph.karno pat.karno meal.cal wt.loss
#1      3  306      2  74   1       1       90       100     1175      NA
#2      3  455      2  68   1       0       90        90     1225      15
#3      3 1010      1  56   1       0       90        90       NA      15
#4      5  210      2  57   1       1       90        60     1150      11

The variable sex has two levels but is coded as a numeric variable here (1 for male, 2 for female or vice versa).

summary(as.factor(sex))
  1   2 
138  90

There's only one coefficient fitted by the model regardless of how you write it:

coxph(Surv(time, status) ~ sex)

# Call:
coxph(formula = Surv(time, status) ~ sex)

      coef exp(coef) se(coef)     z      p
sex -0.531     0.588    0.167 -3.18 0.0015

Likelihood ratio test=10.6  on 1 df, p=0.00111  n= 228, number of events= 165 

coxph(Surv(time, status) ~ as.factor(sex))
Call:
coxph(formula = Surv(time, status) ~ as.factor(sex))

                  coef exp(coef) se(coef)     z      p
as.factor(sex)2 -0.531     0.588    0.167 -3.18 0.0015

Likelihood ratio test=10.6  on 1 df, p=0.00111  n= 228, number of events= 165

For the variable ph.ecog there are 4 levels

summary(as.factor(ph.ecog))
#   0    1    2    3 NA's 
#  63  113   50    1    1

On fitting the survival model against ph.ecog it really does make a difference whether the variable enters as a numeric or a factor. If treated numerically, only a single coefficient is fitted (for a given individual, the value for ecog is multiplied by this coefficient before entering into the coxph calculation);

coxph(Surv(time, status) ~ ph.ecog)
Call:
coxph(formula = Surv(time, status) ~ ph.ecog)

         coef exp(coef) se(coef)   z       p
ph.ecog 0.476      1.61    0.113 4.2 2.7e-05

Likelihood ratio test=17.6  on 1 df, p=2.77e-05  n= 227, number of events= 164 
   (1 observation deleted due to missingness)

However, treated as a factor, three different coefficients will be fitted, one for each non-reference level (ie, levels 1 2 and 3 each have a coefficient) and for a given individual you would look up the coefficient corresponding to the level of the ecog factor.

> coxph(Surv(time, status) ~ as.factor(ph.ecog))
Call:
coxph(formula = Surv(time, status) ~ as.factor(ph.ecog))

                     coef exp(coef) se(coef)    z       p
as.factor(ph.ecog)1 0.369      1.45    0.199 1.86 6.3e-02
as.factor(ph.ecog)2 0.916      2.50    0.225 4.08 4.5e-05
as.factor(ph.ecog)3 2.208      9.10    1.026 2.15 3.1e-02

Likelihood ratio test=18.4  on 3 df, p=0.000356  n= 227, number of events= 164 
   (1 observation deleted due to missingness)

Look into how the coefficients enter the survival model in a good Generalised linear model book (I really can't explain that quickly for you)