I have big data frame. In the "0" column my variable names are recorded (i.e. gene names / AGI) however, there's no column name for this column (this df derived from DESeq).
I want to use the gather function to summarize data. How can I drop "0" column when there is no column name?
For an e.g.
If there is a column name (e.g. gene names / AGI) I know how to do this like below)
df1 <- structure(list(AGI = c("ATCG01240", "ATCG01310", "ATMG00070"), aox2_0h__1 = c(15.79105291, 14.82652303, 14.70630068), aox2_0h__2 = c(16.06494674, 14.50610036, 14.52189807), aox2_0h__3 = c(14.64596287, 14.73266459, 13.07143141), aox2_0h__4 = c(15.71713641, 15.15430026, 16.32190068 ), aox2_12h__1 = c(14.99030606, 15.08046949, 15.8317372), aox2_12h__2 = c(15.15569857, 14.98996474, 14.64862254), aox2_12h__3 = c(15.12144791, 14.90111092, 14.59618842), aox2_12h__4 = c(14.25648197, 15.09832061, 14.64442686), aox2_24h__1 = c(15.23997241, 14.80968391, 14.22573239 ), aox2_24h__2 = c(15.57551513, 14.94861669, 15.18808897), aox2_24h__3 = c(15.04928714, 14.83758685, 13.06948037), aox2_24h__4 = c(14.79035385, 14.93873234, 14.70402827), aox5_0h__1 = c(15.8245918, 14.9351844, 14.67678306), aox5_0h__2 = c(15.75108628, 14.85867002, 14.45704948 ), aox5_0h__3 = c(14.36545859, 14.79296855, 14.82177912), aox5_0h__4 = c(14.80626019, 13.43330964, 16.33482718), aox5_12h__1 = c(14.66327372, 15.22571466, 16.17761867), aox5_12h__2 = c(14.58089039, 14.98545497, 14.4331578), aox5_12h__3 = c(14.58091828, 14.86139511, 15.83898617 ), aox5_12h__4 = c(14.48097297, 15.1420725, 13.39369381), aox5_24h__1 = c(15.41855602, 14.9890092, 13.92629626), aox5_24h__2 = c(15.78386057, 15.19372889, 14.63254456), aox5_24h__3 = c(15.55321382, 14.82013321, 15.74324956), aox5_24h__4 = c(14.53085803, 15.12196994, 14.81028556 ), WT_0h__1 = c(14.0535031, 12.45484834, 14.89102226), WT_0h__2 = c(13.64720361, 15.07144643, 14.99836235), WT_0h__3 = c(14.28295759, 13.75283646, 14.98220861), WT_0h__4 = c(14.79637443, 15.1108037, 15.21711524 ), WT_12h__1 = c(15.05711898, 13.33689777, 14.81064042), WT_12h__2 = c(14.83846779, 13.62497318, 14.76356308), WT_12h__3 = c(14.77215863, 14.72814995, 13.0835214), WT_12h__4 = c(14.70685445, 14.98527337, 16.12727292), WT_24h__1 = c(15.43813077, 14.56918572, 14.92146565 ), WT_24h__2 = c(16.05986898, 14.70583866, 15.64566505), WT_24h__3 = c(14.87721853, 13.22461859, 16.34119942), WT_24h__4 = c(14.92822133, 14.74382383, 12.79146694)), class = "data.frame", row.names = c(NA, -3L))
sdf1 <- gather(df1, "group", "Expression",-AGI) %>% separate(group, c("sample", "time", "r")) %>% unite(tgroup, c("sample", "time")) %>% group_by(AGI, tgroup) %>% summarize(expression_mean = mean(Expression)) %>% spread(tgroup, expression_mean) %>% column_to_rownames(colnames(.)[1])
Above sample AGI is in the first column, my current working df's this column is in "0" column and it has not named as "AGI"
Q1- How can I drop "0" column for gather?
Q2 - How can I give a column name to "0" column (i.e. AGI)?
1 answer
This column 0 can be accessed via rownames. You cannot give it a name but could include it into the data frame:
sdf2 <- cbind(AGI=rownames(sdf1), sdf1)
By the way, for the future I suggest you indicate which packages are necessary to run your code if you post code, in this case dplyr, tibble and tidyr.
Log in to answer this question.

Read about rownames_to_column