Structural variation annotation is different in VCF. Please refer to the guidelines VCF format v4.2.

For your example:

1   25688926    DUP_gs_CNV_1_25688926_25700415  G   <CN0>,<CN2> .   PASS    SVTYPE=CNV;END=25700415;CS=DUP_gs;AC=101,12;AF=0.02016773,0.00239617;NS=2504;AN=5008;EAS_AF=0.0169,0.004;EUR_AF=0.007,0.001;AFR_AF=0.0492,0.0015;AMR_AF=0.013,0.0014;SAS_AF=0.0031,0.0041   GT

• Chromosome: 1
• Start: 25688926
• End: 25700415
• Type: multiallelic CNV
• Reference Allele: Copy Number 1
• Alternate Alleles: Copy Number 0, Copy Number 2

On genotypes:

0|0:  copy number 2
0|1: copy number 1 (1 + 0)
0|2: copy number 3 (1+ 2)
1|2: copy number 2 (0 + 2)
2|2: copy number 4 (2 + 2)

If you want to parse a vcf in perl

#!/usr/bin/perl
open IN, $ARGV[0];
while(<IN>){
    next if ($_ =~ /^\#/);
    chomp $_;
     my @r = split /\t/, $_;
     my @info = split /\;/, $r[7];
     undef my $e;
     foreach(@info) { if ($_ =~ /END=/) { $e=$_; $e =~ s/END=//; }}
     print $r[0],"\t",$r[1],"\t",$e,"\n";
}
close IN;

In python

#!/usr/env python
import sys
with open(sys.argv[1],'r') as f:
    for l in f:
            if l.startswith('#'): continue
            r = l.rstrip('\n').split('\t')
            e=''
            for x in r[7].split(';'):
                    if 'END=' in x: e=x.replace('END=','')
           print r[0],r[1],e