That returns with zero characters in it! Do you know any other way?
> fls
character(0)
In the script I am running there is this line:
fls <- list.files("./tophat_all", pattern="bam$", full.names = T)
Is there any possible way to list files from different directories, like below?
fls <- list.files("D:/tophat_all/nmtasync_R1noT.bam", "D:/allfiles/tophat_all/wtasync_R1noT.bam", "C:/etc./tophat_all/wtasync_R2noT.bam", pattern="bam$", full.names = T)
My life will be way easier if I can do that!
Use a vector of dir names as first argument:
fls <- list.files(c("D:/tophat_all/nmtasync_R1noT.bam",
"D:/allfiles/tophat_all/wtasync_R1noT.bam",
"C:/etc./tophat_all/wtasync_R2noT.bam"),
pattern="bam$", full.names = TRUE)
That returns with zero characters in it! Do you know any other way?
> fls
character(0)
I did not look at you code carefully - you provide files in list.files, when directories are expected. The list of files is what the function will return. Try something like
fls <- list.files(c("D:/tophat_all/",
"D:/allfiles/tophat_all/",
"C:/etc./tophat_all/"),
pattern="bam$", full.names = TRUE)
Thanks! In the beginning the idea was to just list specific files from different directories. But this also helps, I will put them in different folders!!! I am not bioinformatists therefore I have a though life working around with codes!
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c()around paths??list.filesshows the path argument takes a character vector (not entirely clear why you're listing files already specified by their absolute path but ok).